2c^2-3c-27=0

Solution for 2c^2-3c-27=0 equation:

Simplifying
2c2 + -3c + -27 = 0

Reorder the terms:
-27 + -3c + 2c2 = 0

Solving
-27 + -3c + 2c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + -1c)(9 + -2c) = 0

Subproblem 1
Set the factor '(-3 + -1c)' equal to zero and attempt to solve:

Simplifying
-3 + -1c = 0

Solving
-3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1c = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1c = 0 + 3
-1c = 0 + 3

Combine like terms: 0 + 3 = 3
-1c = 3

Divide each side by '-1'.
c = -3

Simplifying
c = -3
Subproblem 2
Set the factor '(9 + -2c)' equal to zero and attempt to solve:

Simplifying
9 + -2c = 0

Solving
9 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -2c = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -2c = 0 + -9
-2c = 0 + -9

Combine like terms: 0 + -9 = -9
-2c = -9

Divide each side by '-2'.
c = 4.5

Simplifying
c = 4.5
Solution
c = {-3, 4.5}